x^2+(3/2)x=10

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Solution for x^2+(3/2)x=10 equation: 


x in (-oo:+oo)

x^2+(3/2)*x = 10 // - 10

x^2+(3/2)*x-10 = 0

x^2+3/2*x-10 = 0

DELTA = (3/2)^2-(-10*1*4)

DELTA = 169/4

DELTA > 0

x = ((169/4)^(1/2)-3/2)/(1*2) or x = (-(169/4)^(1/2)-3/2)/(1*2)

x = 5/2 or x = -4

x in { -4, 5/2 }

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